Man varargs
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Description
A function uses "varargs", short for "variable arguments", if it intentionally may be called with less or more arguments than formally specified.
The proper order to define a function call is:
[ modifier ] [ varargs ] [ return type ] function( args...)
Any other order will result in an error.
Given a function definition like this:
void fun (string arg1, int arg2, int arg3)
fun() has to be called with exactly three parameters: one string and two integers.
If the function is defined as
varargs void fun (string arg1, int arg2, int arg3)
it is possible to call the function with just arg1, or arg1 and arg2. The remaining unspecified arguments (arg2 and arg3, resp. arg3) are in these cases assumed to be 0.
To pass more arguments than specified, the functions last
parameter must be defined as following:
void fun (string arg1, int arg2, varargs int * arg3)
This allows fun() to be called with three or more arguments. The arguments, except those assigned to the other parameters, in this case arg1 and arg2, and collected into an array which is then passed as arg3. For example
fun("foo", 1) -> arg3 == ({ })
fun("foo", 1, 2) -> arg3 == ({ 2 })
fun("foo", 1, 2, 3) -> arg3 == ({ 2, 3 })
The type of the varargs argument has to be an array of the expected type (int*, object*, string*, ...); in this case, only integers are allowed. To accept arguments of any kind, define the parameter as 'varargs mixed' or 'varargs mixed*'.
To 'flatten' the received argument array in your own function calls, use the efun apply(); e.g.:
apply(#'call_out, 1, arg3)
The two varargs variants can of course be combined:
varargs void fun (string arg1, int arg2, varargs int* arg3)
defines a function which may be called with any number of arguments.
History
The possibility to pass more arguments than formally specified was introduced in 3.2.1@132. Before, the excess arguments were silently ignored.
